启动在不同包定义的服务?
问题说明
我有两个应用程序，一个在命名空间 com.gtosoft.voyager 中运行，另一个是 com.gtosoft.dash.从 com.gtosoft.dash 我想启动在 com.gtosoft.voyager 中定义的服务...
I have two apps, one runs in namespace com.gtosoft.voyager and the other is com.gtosoft.dash. From com.gtosoft.dash I would like to start up the service which is defined in com.gtosoft.voyager...
我想我需要一个意图，但是在用 startService() 启动它之前，我会传递给意图什么参数?
I think I need an intent, but what arg(s) would I pass to the intent before kicking it off with startService()?
如果它们在同一个包中，我可以使用
If they were in the same package I could just use
Intent svc=new Intent (SettingsActivity.this,VoyagerService.class);
startService(svc);
定义服务的清单片段
<application android:icon="@drawable/voyagercarlogo" android:label="@string/app_name" android:debuggable="false">
<provider android:name="com.gtosoft.voyager.VoyagerCProvider"
android:authorities="com.gtosoft.voyager"/>
<service android:name=".VoyagerService"/>
<activity android:name=".SettingsActivity"
android:label="Voyager"
android:configChanges="keyboardHidden|orientation">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
正确答案
我会在服务上设置一个 ，使用自定义操作，然后在您的Intent 启动或绑定到该服务.你可以在这对 client 中看到一个例子和 service 示例项目.
I would set up an <intent-filter> on the service, with a custom action, and then use it in your Intent to start or bind to that service. You can see an example of that in this pair of client and service sample projects.
这篇好文章是转载于：学新通技术网
