使用带有 SQL 的数据透视表列转置为行
it1352
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问题说明
MS SQL Server 2012
MS SQL Server 2012
我有一个名为 indexrows
name displayname propertyvalue
abc $row1 agg
abc $row2 spx
abc $row3 qqq
def $row1 spx
def $row2 qqq
我想将这些结果转置为如下所示.
I would like to transpose these results to look like this.
name $row1 $row2 $row3
abc agg spx qqq
def spx qqq
我尝试了以下查询但没有成功.我收到此错误
I tried the following query without success. I get this error
消息 156，级别 15，状态 1，第 10 行关键字for"附近的语法不正确.
Msg 156, Level 15, State 1, Line 10 Incorrect syntax near the keyword 'for'.
select *
from (
select
name,propertyvalue, displayname
from indexrows
) a
PIVOT
(
propertyvalue
for [displayname] in ('$row1', '$row2', '$row3')
) as pivot
感谢任何帮助.
正确答案
#1
您的查询有一些问题.
首先，您在 PIVOT 上缺少聚合函数.您需要围绕 propertyvalue 进行聚合.
First, you are missing an aggregate function on your PIVOT. You need an aggregate around propertyvalue.
其次，您需要用方括号而不是单引号将 $row1 等括起来.
Second, you need to surround the $row1, etc with square brackets not single quotes.
第三，我会为 as pivot
因此代码将是:
select *
from
(
select name, propertyvalue, displayname
from indexrows
) a
pivot
(
max(propertyvalue)
for [displayname] in ([$row1], [$row2], [$row3])
) piv;
这篇好文章是转载于：学新通技术网
