为什么我得到PHP无效的JWT提供的错误?

从以下项生成的密钥: https://web-push-codelab.glitch.me/

keys generated from: https://web-push-codelab.glitch.me/

响应已通过以下方式验证: https://jwt.io/

response validated with: https://jwt.io/

返回的令牌有效！但我在chrome开发人员控制台中收到以下错误: 提供了无效的JWT"

Token being returned is valid! and yet I get the following error in chrome developer console: "invalid JWT provided"

为什么我的代码不起作用?

Why isnt my code working?

代码:

function base64url_encode($data) {
    return rtrim(strtr(base64_encode($data), ' /', '-_'), '=');
}



// Create token header as a JSON string
$header = json_encode(["alg" => "ES256","typ" => "JWT"]);

// Create token payload as a JSON string
$payload = json_encode(["aud" => "https://fcm.谷歌apis.com","exp" => time()   3600,"sub" => "mailto:push@example.com"]);



// Encode Header to Base64Url String
$base64UrlHeader = base64url_encode($header);

// Encode Payload to Base64Url String
$base64UrlPayload = base64url_encode($payload);



// Create Signature Hash
$signature = hash_hmac("SHA256", $base64UrlHeader . "." . $base64UrlPayload, "PRIVATE_KEY", true);


// Encode Signature to Base64Url String
$base64UrlSignature = base64url_encode($signature);




// Create JWT
$token = $base64UrlHeader . "." . $base64UrlPayload . "." . $base64UrlSignature;



$key = "PUBLIC_KEY";


$ch = curl_init();

curl_setopt($ch, CURLOPT_URL, 'https://fcm.谷歌apis.com/fcm/send/.....');
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_POST, 1);

$headers = array();
$headers[] = "Ttl: 60";
$headers[] = "Content-Length: 0";
$headers[] = "Authorization: vapid t=".$token.",k=".$key."";
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);

$result = curl_exec($ch);

curl_close($ch);


echo json_encode($result);