Cronjob:找不到命令
问题说明
我的cronjob如下:
I have a cronjob that is the following:
*/10 * * * * root cd /some/directory && python3 FILE.py >> Output.txt 2>&1
如果我从常规命令行运行该命令，它将正常工作.但是当从cronjob运行时，我得到/bin/sh:python3:找不到
if i run that command from a regular command line, it works fine. But when ran from cronjob, I get /bin/sh: python3: not found
但是当我运行 echo $ PATH 时，它会返回
But when I run echo $PATH it returns
/sbin:/bin:/usr/sbin:/usr/bin:/usr/syno/sbin:/usr/syno/bin:/usr/local/sbin:/usr/local/bin:/usr/local/python3/bin:/opt/bin
(请注意，此目录中包含/usr/local/python3/bin
(Note that /usr/local/python3/bin is included in this directory
我该如何解决?
正确答案
cronjob的环境似乎与交互式shell不同.您可以编辑cronjob以使用绝对路径来调用该python脚本.或者，您可以编写wrapper sh脚本来准确设置python脚本所需的环境，然后让cronjob执行该脚本.
It seems like cronjob has a different environment than your interactive shell. You could edit the cronjob to use an absolute path to call that python script. Or you can write a wrapper sh script to setup exactly the environment required by the python script and have cronjob execute that.
https://askubuntu.com/questions/23009/reasons-why-crontab-不工作
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