没办法调用任何构造函数?
问题说明
public class Test {
public static void main(String args[]){
System.out.println("Main");
Test2 test2 = new Test2();
}
}
class Test2 {
Test2() {
System.out.println("Inside Test2");
//do something
}
Test3 test = new Test3();
}
class Test3 {
Test3() {
System.out.println("Inside Test3");
//do something
}
Test2 test2 = new Test2();
}
在这里我想了解为什么为什么 Test 类的主要方法中的 Test2 test2 = new Test2(); 语句不能调用类的构造函数> Test2 和类似地 Test2 中的 Test3 test = new Test3(); 无法调用类 Test3 的构造函数.
Here I wanted to understand why this statement Test2 test2 = new Test2(); in main method of class Test is not able to invoke the constructor of class Test2 and similarly Test3 test = new Test3(); in Test2 is not able to invoke the constructor of class Test3.
我想了解这种行为的原因吗?
Here I wanted to understand the reason for this behavior?
预期输出: Test2里面的主要内容
当前输出: Main 并显示错误
Expected Output : Main Inside Test2 Inside Test3
Current Output: Main with this error
Exception in thread "main" java.lang.StackOverflowError
at com.practice.stackoverflow.Test3.<init>(Test.java:26)
at com.practice.stackoverflow.Test2.<init>(Test.java:17)
at com.practice.stackoverflow.Test3.<init>(Test.java:26)
正确答案
Test2 创建一个新的 Test3 对象...从而创建一个新的 Test2 对象...等等.
Test2 makes a new Test3 object... which makes a new Test2 object... so on.
您尝试创建无限数量的对象，因此自然会收到StackOverflowError.
You are attempting to create an infinite amount of objects, so naturally you will get a StackOverflowError.
以下方法将起作用:
public class Test {
public static void main(String args[]){
System.out.println("Main");
Test2 test2 = new Test2();
}
}
class Test2 {
Test2() {
System.out.println("Inside Test2");
//do something
}
Test3 test = new Test3();
}
class Test3 {
Test3() {
System.out.println("Inside Test3");
//do something
}
Test4 test4 = new Test4();
}
class Test4 {
Test4() {
System.out.println("Inside Test4");
}
}
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