Slim PHP 的默认 GET 路由
问题说明
我最近使用 Slim PHP 框架构建了一个小型 API，它运行良好.但是，我想为根/"设置一个 GET 路由，该路由以基本消息响应，并让任何其他 GET 请求返回拒绝访问".
I've recently built a small API using the Slim PHP framework and it is working great. I would however like to set a GET route for the root "/" which responds with a basic message and have any other GET requests return an "access denied".
在阅读文档和各种示例后，我无法弄清楚如何完成这些任务.我的项目仅依赖于 POST 路由，但能够响应针对根域和任何其他页面的 GET 请求将非常棒.
Upon reading both the documentation and various examples, I have not been able to figure out how to accomplish either of these tasks. My project only relies on POST routes but being able to respond to GET requests aimed at both the root domain and any other pages would be fantastic.
代码:
// SLIM INSTANCE
$app = new SlimSlim();
$app->contentType('application/json');
// SLIM ROUTES
$app->group('/core', function() use ($app)
{
$app->post( '/create', 'Create' );
$app->post( '/start', 'Start' );
$app->post( '/stop', 'Stop' );
$app->post( '/delete', 'Delete' );
});
正确答案
如果你想响应不同的方法，只需使用map()-方法:
if you want to respond to different methods, just use the map()-Method:
$app->map('/create', 'Create')->via('GET', 'POST');
要注册一个默认路由"，如果没有匹配的路由，它将始终回复拒绝访问"，您可以覆盖notFound"处理程序:
To register a 'default route', which will always reply with 'access denied' if no route matched, you can override the 'notFound'-Handler:
$app->notFound(function () use ($app) {
$app->response->setStatus(403);
//output 'access denied', redirect to login page or whatever you want to do.
});
要完成'root'-route:$app->get('/',function(){/*...*/}); 应该就是这样.
To accomplish a 'root'-route: $app->get('/',function(){/*...*/}); should to exactly this.
这篇好文章是转载于：学新通技术网
