力扣LeetCode双重vector杨辉三角C、C++

1.C实现

#include<stdio.h>
#include<stdlib.h>
#include<assert.h>

int** generate(int n, int* rnum_row, int** rnum_row_ele) 
{
    //*rnum_row-->num_row：杨辉三角行数
    *rnum_row = n;
   
    //*rnum_row_ele-->num_row_ele：一级指针 指向一维数组 n个int-->每一行元素个数
    *rnum_row_ele = (int*)malloc(sizeof(int) * n);
   
    //a：二级指针 指向一个一维数组 n个int* 每一个int*指向一个一维数组-->存放杨辉三角数据
    int** a = (int**)malloc(sizeof(int*) * n);
    
    for (int i = 0; i < n;   i)
    {
        //第i行 i 1个数据   *(a   i)：一级指针 指向一个一维数组 --> 存放杨辉三角数据
        *(a   i) = (int*)malloc(sizeof(int) * (i   1));
        //首尾均为1
        a[i][0] = a[i][i] = 1;
        //第i行 元素个数i 1
        *((*rnum_row_ele)   i) = i   1;

        for (int j = 1; j < i;   j)
        {
            a[i][j] = a[i - 1][j]   a[i - 1][j - 1];
        }
    }
    return a;
}
int main()
{
    int n = 0;  //输出n行杨辉三角的内容
    scanf("%d", n);

    int num_row = 0; //杨辉三角行数

    int* num_row_ele = NULL;//一级指针 指向一个一维数组 存放每一行元素个数

    int** arr = generate(n, &num_row, &num_row_ele);

    // 输出结果
    for (int i = 0; i < num_row;   i)
    {
        for (int j = 0; j < *(num_row_ele   i);   j)
        {
            printf("%d ", arr[i][j]);
        }
        printf("\n");
    }

    // 释放内存
    for (int i = 0; i < num_row;   i)
    {
        free(arr[i]);
    }
    free(arr);
    free(num_row_ele);

    return 0;
}

2.C 实现

#include <iostream>
#include <vector>
#include <string>
using namespace std;
class Solution
{
public:
	//Solution类的公有成员函数
	vector<vector<int>> generate(int numRows)
	{
		vector<vector<int>> vv;
		vv.resize(numRows);
		for (size_t i = 0; i < vv.size();   i)
		{
			//第i行 i 1个数据 初始化0
			vv[i].resize(i   1, 0);
			//头尾为1
			vv[i].front() = vv[i].back() = 1;
		}
		for (size_t i = 0; i < vv.size();   i)
		{
			for (size_t j = 0; j < vv[i].size();   j)
			{
				if (vv[i][j] == 0)
					vv[i][j] = vv[i - 1][j]   vv[i - 1][j - 1];
			}
		}
		return vv;
	}
};
int main()
{
	int n = 0;
	scanf("%d", n);
	Solution s;
	vector<vector<int>> ret = s.generate(n);
    for (size_t i = 0; i < ret.size();   i)
	{
		for (size_t j = 0; j < ret[i].size();   j)
		{
			cout << ret[i][j] << " ";
		}
		cout << endl;
	}

	return 0;
}

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