go Interface{} 转int

        go中interface类型很好用，但是有时候用了就没办法作为键值了  这点就比较头痛了，这里介绍一种转换方法，非常好用

1.  
   func GetInterfaceToInt(t1 interface{}) int {
2.  
   var t2 int
3.  
   switch t1.(type) {
4.  
   case uint:
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   t2 = int(t1.(uint))
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   break
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   case int8:
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   t2 = int(t1.(int8))
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   break
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    case uint8:
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    t2 = int(t1.(uint8))
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    break
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    case int16:
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    t2 = int(t1.(int16))
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    break
16.  
    case uint16:
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    t2 = int(t1.(uint16))
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    break
19.  
    case int32:
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    t2 = int(t1.(int32))
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    break
22.  
    case uint32:
23.  
    t2 = int(t1.(uint32))
24.  
    break
25.  
    case int64:
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    t2 = int(t1.(int64))
27.  
    break
28.  
    case uint64:
29.  
    t2 = int(t1.(uint64))
30.  
    break
31.  
    case float32:
32.  
    t2 = int(t1.(float32))
33.  
    break
34.  
    case float64:
35.  
    t2 = int(t1.(float64))
36.  
    break
37.  
    case string:
38.  
    t2, _ = strconv.Atoi(t1.(string))
39.  
    if t2 == 0 && len(t1.(string)) > 0 {
40.  
    f, _ := strconv.ParseFloat(t1.(string), 64)
41.  
    t2 = int(f)
42.  
    }
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    break
44.  
    case nil:
45.  
    t2 = 0
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    break
47.  
    case json.Number:
48.  
    t3, _ := t1.(json.Number).Int64()
49.  
    t2 = int(t3)
50.  
    break
51.  
    default:
52.  
    t2 = t1.(int)
53.  
    break
54.  
    }
55.  
    return t2
56.  
    }

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